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1.2 课后习题详解
§1 函数的概念
1.解下列不等式,并画出x的范围:
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解:
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图1-1
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图1-2
(3)或
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图1-3
(4)−4<x≤0或2≤x<4
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图1-4
2.证明下列绝对值不等式:
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证明:(1)因则
于是
.
(2)用数学归纳法证明.
①当n=2时,由得结论成立.
②假设当n=k时结论成立,即有
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则当n=k+1时,
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综上可知,对一切自然数n,均成立.
(3)
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3.解下列绝对值不等式,并画出x的范围:
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解:
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图1-5
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图1-6
(3)当A≥0时,x<-A或x>A;
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图1-7
当A<0时,x∈R.
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图1-8
(5)原式等价于则
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图1-9
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图1-10
4.求下列函数的定义域及它在给定点上的函数值:
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的定义域及f(-1),f(1)和f(2);
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的定义域及y(4),y(5);
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的定义域及f(0),f(-1).
解:(1)函数的定义域为
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(2)函数的定义域为
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(3)函数的定义域为
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(4)函数的定义域为
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(5)函数的定义域为
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(6)函数的定义域为
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5.求下列函数的定义域和值域:
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解:(1)函数的定义域为值域为
(2)函数的定义域为,值域为
.
(3)函数的定义域为,值域为
(4)函数的定义域为
6.设f(x)=x+1,φ(x)=x-2,试解方程|f(x)+φ(x)|= |f(x)|+|φ(x)|.
解:由题意可得,即
则x≥2或x≤-1.
7.设f(x)=(|x|+x)(1-x),求满足以下各式的x值:
(1)f(x)=0; (2)f(x)<0.
解:(1)要f(x)=0,则或1-x=0,即x≤0或x=1.
(2)因则要f(x)>0,只要1-x<0即可,即x>1.
8.图1-11表示电池组V、固定电阻R0和可变电阻R组成的电路.在一段不长的时间内,A,B两点间的电压V可以看成一个常量,求出电流I和可变电阻R的函数式.
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图1-11
解:由题意及物理学知识,得
9.在一个圆柱形容器内倒进某种溶液,该圆柱形容器的底半径是a,高为h,倒进溶液的高度是x(图1-12),求该溶液的体积V和x之间的函数关系V=V(x),并写出它的定义域和值域.
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图1-12
解:由题意得.
10.某灌溉渠的横断面是一个梯形,如图1-13,底宽2m,斜边的倾角为45°,CD表示水面,求断面ABCD的面积S与水深h的函数关系.
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图1-13
解:由题意及图可得.
11.有一深为H的矿井,如用半径为R的卷扬机以角速度w从矿井内起吊重物,求重物底面与地面的距离s和时间t的函数关系(图1-14).
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图1-14
解:由题意及图可得.
12.设
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求f(-2),f(-1),f(0),f(1)和
解:由题意得
13.设
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求f(0),f(-2),f(t+1),f(a).
解:由题意得
,
.
14.邮资y是信件质量x的函数.假设我们规定,对于国内的外埠平信,按信件质量,每重20g应付邮资8分,不足20g者以20g计算.当信件的质量在60g以内时,试写出这个函数的表达式,并画出它的图形.
解:由题意得
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函数图如下所示:
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图1-15
15.脉冲发生器产生一个三角波,其波形如图1-16,写出函数关系u= u(t)(0≤t≤20).
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图1-16
解:由题意及图可得
16.下列函数f和φ是否相等,为什么?
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解:(1)因f的定义域为,故这两个函数不相等.
(2)因故这两个函数的函数表达式不一样,故这两个函数不相等.
(3)因恒成立,故这两个函数相等.
17.证明对于直线函数f(x)=ax+b,若自变量组成一等差数列,则对应的函数值
也组成一等差数列.
证明:设是xn中任意3个相邻的数
据题意,得
,
又
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则
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于是
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从而
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又
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是xn中任意3个相邻的数,则
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是yn中任意3个相邻的数,于是
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也组成一等差数列.
18.如果曲线y=f(x)上的任一条弦都高出于它所限的弧(图1-17),证明不等式
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对于所有的成立(凡具有上述特性的函数叫做凸函数).
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图1-17
证明:在曲线上任取两点连接AB取其中点
则
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又曲线上
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所对点的纵坐标为
,
则
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又曲线上的任一条弦都高于他所限的弧且
为弦与弧的交点,则
,
则
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对于所有的成立.
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图1-18
19.讨论下列各函数在所示区间内的单调性:
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解:(1)设
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则
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又
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则
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故当时,原函数严格单调递减;当
时,原函数严格单调递增.
(2)设
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则
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又
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则
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于是
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故当时,原函数严格单调递增.
(3)设
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则
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又
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即
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于是
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故当时,原函数严格单调递减.
20.讨论下列函数的奇偶性:
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这个函数称为符号函数;
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解:(1)因
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则
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故
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于是,此函数是非奇非偶函数.
(2)因
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则
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于是此函数是偶函数.
(3)因
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则
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故
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于是,此函数是非奇非偶函数.
(4)因
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则
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于是此函数是偶函数.
(5)因

则

于是此函数是奇函数.
(6)因

则

故

于是,此函数是非奇非偶函数.
21.试证两个偶函数的乘积是偶函数,两个奇函数的乘积是偶函数,一个奇函数与一个偶函数的乘积是奇函数.
证明:设为定义在
内的偶函数,
为定义在
内的奇函数,

则

于是

从而F1(x)是偶函数;F2(x)是偶函数;F3(x)是奇函数.
22.设f(x)为定义在(-∞,+∞)内的任何函数,证明是偶函数,
是奇函数.写出对应于下列函数的

证明:因

则

是偶函数;
又

则

是奇函数.

23.说明下列函数哪些是周期函数,并求最小正周期:

解:(1)因

则

(2)假设

为一周期函数,且

据周期函数的定义,对任何

有

特别对x=0也应该成立,则

于是

又对

也成立,故

于是

又

而则假设不成立,即函数

不是周期函数.
(3)因

的T=π,则

的T=2π.
(4)
(5)因

故可知


(6)因

的T=π,则

的T=π.
(7)因

则

的T=1.
(8)
§2 复合函数和反函数
1.下列函数组能否构成复合函数y=f(φ(x)),如果能够构成则指出此复合函数的定义域和值域:

,定义域为
,定义域为X,值域为U2;

解:(1)因的定义域为
的值域为
则此函数能构成复合函数
它的定义域为
值域为
(2)因的定义域为
的值域为
则此函数能构成复合函数
它的定义域为
值域为
(3)因的定义域为
.

则此函数能构成复合函数

它的定义域为值域为
.
(4)因的定义域为
的值域为U2.
当时,此函数能构成复合函数y=2,它的定义域视具体函数而定,值域为
;
当时,此函数不能构成复合函数.
(5)因的定义域为
的值域为
;则此函数能构成复合函数
它的定义域为
值域为
.
2.设,证明:

证明:由题意得

3.(1)设,求
(2)设,求
(3)设,求
(4)设,求f(a tanx).
解:(1)因

则

(2)因

则

(3)因

则

(4)因

则

4.若.求
解:因

则

5.若,求
解:因
,
则



6.设,求
解:因

则


7.求下列函数的反函数及反函数的定义域:

解:(1)因

则

从而此函数的反函数为

(2)因

则

从而此函数的反函数为

(3)因

则

从而此函数的反函数为


(4)因
,
则

从而此函数的反函数为

§3 基本初等函数
1.把下列在[0,1)上定义的函数延拓到整个实轴上去,使它成为以1为周期的函数:

解:(1)延拓后的函数为

(2)延拓后的函数为

(3)延拓后的函数为

2.把下列在[0,+∞)上定义的函数延拓到整个实轴上去,(a)使它们成为奇函数,(b)使它们成为偶函数:

解:(1)延拓后的函数为:

(2)延拓后的函数为:

3.作下列函数的图形:

解:

图1-19
4.作函数的图形.
解:

图1-20
5.作函数的图形.
解:

图1-21
6.一个函数是用下述方法决定的:在每一个区间n≤x<n+1(其中n为整数)f(x)是线性的且,试作此函数的图形.
解:

图1-22
7.作函数的图形.
解:

图1-23
8.若已知函数,作下列函数的图形:

解:(1)

图1-24
(2)(k,b>0)

图1-25
(3)

图1-26
9.若已知函数的图形,作函数
的图形,并说明
的图形与y的图形的关系.
解:设的图形如下:

图1-27
则y1的图形为:

图1-28
则y2的图形为:
图1-29
则y3的图形为:

图1-30
y1的图形当时与y的图形关于x轴对称;当
时与y的图形一样,
y2的图形与y的图形关于y轴对称,
y3的图形与y的图形关于原点对称.
10.若已知的图形,试作函数
的图形,并说明y的图形与
的图形的关系.
解:

图1-31
11.对于定义在[0,π]上的函数y=x,先把它延拓到[0,2π]使它关于x=π为对称,然后再把已延拓到[0,2π]上的函数延拓到整个实轴上使函数成为以2π为周期的函数,并作出它的图形.
解:所求函数为:



图1-32